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  1. Home/
  2. Tribhuvankumar Pandit/
  3. Week 11 Car Crash simulation

Week 11 Car Crash simulation

Aim- For this project, we will have to perform a parametric study using 3 different values of thickness for the car body by expicit dynamics. Procedure- Here no non-linear material has been not specified to us, so we will use the materials as follow for Car body, Stainless Steel NL- 2. Structural Steel for wall. Now we…

    • Tribhuvankumar Pandit

      updated on 04 Jul 2022

    Aim-

    For this project, we will have to perform a parametric study using 3 different values of thickness for the car body by expicit dynamics.

    Procedure-

    • Here no non-linear material has been not specified to us, so we will use the materials as follow for Car body,

    Stainless Steel NL-

    2. Structural Steel for wall.

    • Now we have to import the model for that right click on the geometry tab and hit import>>then select the file from saved location and hit ok.

    Symmetry-

    • Now we have to give symmerty to wall and car body since both models are halfly captured.
    • To do so right click on model>>symmetry>>symmetry region>>select wall side face along x-axis as normal.

    • For car side face for symmetry region.

    Connections-

    • Here we dont define ady contact as it is not required so we will delete the existing contacts and keep body interactions.

    Mesh-

    • For wall we have to insert a patch method as tetrahedrons.

    • For car body we have to select method as triangles since it has lesser thickness than 6mm, so we will consider it as 2d element.

    • Now we have to insert the sizing for side of car body.

    • For rest keep default mesh size and hit mesh.

    Analysis Setting-

    • Here we will give time step as 1e-3 and max. and rest of settings as default.

    • As we are going to move wall so, we will fix car as rigid body.

    • We will give displacement load to wall back side with ramped 500mm.

    Solution Setting-

    • Here we have to define total deformation, to do so right click solution>>insert>>deformation>>Total.
    • Now for stress right click on the solution>>insert>>stresses>>equivalent (von-Mises).

    Parametric setting-

    • As per given condition we have to evaluate the result for 3 different thickness by parametric form.
    • We need to give parametric value to total deformation and equivalent stress also.

    • Now parametric window will appear in the projects tab.

    • Now input rest as 0.4mm and 0.5mm thickness to it in parametric settings.

    Results-

    Total Deformation-

    Case-1-0.3mm

    Case-2-0.4mm

    Case-3-0.5mm

    Equivalent Stress-

    Case-1-0.3mm

    Case-2-0.4mm

    Case-3-0.5mm

    Result Comparision-

    Cases

    Total Deformation (mm)

    Equivalent Stress (MPa)

    Min.

    Max.

    Min.

    Max.

    Case-1

    0

    1047.22

    0

    12293.23

    Case-2

    0

    1045.12

    0

    12237

    Case-3

    0

    1042.87

    0

    12179.16

    • From above table we can observe that with increase in thickness total deformation and equivalent stress decrease.

    Animated Results-

    Case-1-0.3mm thickness 

    Total Deformation

    Equivalent Stress

    Case-2-0.4mm thickness 

    Total Deformation

    Equivalent Stress

    Case-3-0.5mm thickness 

    Total Deformation

    Equivalent Stress

    Conclusion-

    • From above simulation we have to select max. thickness for safe condition what we can conclude now.
    • But in actual its not about metal thickness, its about how the energy of impact is absorbed.
    • We will have to understand that the sheet metal doesn't contribute totally during crash, its the internal structure which decides fate of the car during crash.

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