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Aim:- To determine the workability of the fresh concrete by using IS 456:2000 and IS 10262:2019 Introduction The process of selecting suitable ingredients for producing concrete of required strength, durability and workability as economical as possible is known as concrete mix design There are 3 types of concrete mixes…
Rajendra Prasad
updated on 23 Jun 2022
Aim:- To determine the workability of the fresh concrete by using IS 456:2000 and IS 10262:2019
Introduction
The process of selecting suitable ingredients for producing concrete of required strength, durability and workability as economical as possible is known as concrete mix design
There are 3 types of concrete mixes are there
Now a days we are using a Nominal mix for small projects and Design mix for large projects which require high strength and durability (as per design)
The materials which required to do the concrete mix are cement, fine aggregate, coarse aggregate and water
These materials should be tested before the concrete mix
Advantages of mix design
Procedure for concrete mix design
Given data
1. Target mean strength
f'ck= fck+1.65*S
f'ck = target average compressive strength at 28 days
fck = characteristic compressive strength at 28days
S = Standard deviation (from table 2 of IS 10262:2019)
2.Selection of water-cement ratio
From table 5 of IS 456:2000 the value can be taken based on the exposure condition
3.Selection of water-content
From table 4 of IS 10262:2019 maximum water content for 20mm aggregate = 186lit (for 25-50mm slump range)
(For additional slump 3% may be added for every 25mm slump)
4. Selection of cement-content
This value is taken from w/c ratio
Minimum cement content is taken from table 5 of IS 456:2000
5. Volume of coarse aggregate and fine aggregate can be determined from table 5 of IS 10262:2019 (selecting depending upon fine aggregate zone)
6. The mix calculation per unit volume of concrete shall be as follows
Mass of chemical admixture = 2% of cementitious material
7. Mix proportion for trial mix
8. Trial mix ratio = cement : fine aggregate : coarse aggregate
Concrete mix design for M-35 grade with fly ash
Aim:- To determine the workability of the fresh concrete by using IS 456:2000 and IS 10262:2019 for concrete mix design for M-35 grade with fly ash
Introduction
The process of selecting suitable ingredients for producing concrete of required strength, durability and workability as economical as possible is known as concrete mix design
Code books used are - IS456:2000 and IS 10262:2019
Step 1 :-Stipulation for proportion
Here all the values, types of ingredients, conditions and methods are assumption except grade of designation because the values are not mentioned in questions
Step 2:- Test data for materials
Step 3:- Target strength mix
f'ck= fck+1.65*S
f'ck = target average compressive strength at 28 days
fck = characteristic compressive strength at 28days
S = Standard deviation
From table 2 of IS 10262:2019 standard deviation S = 5 N/mm^2
f'ck = 35+1.65*5
f'ck = 43.25 N/mm^2
Target mean strength = 43.25 N/mm^2
Step 4:- Selection of water-cement ratio
From table 5 of IS 456:2000 for severe exposure maximum water-cement ratio = 0.45
By using a fig 1 of IS 10262:2019 w/c ratio = 0.38
0.38<0.45 ( take lesser value)
Water-cement ratio = 0.38
Hence ok
Step 5:- Selection of water content
From table 4 of IS 10262:2019 maximum water content for 20mm aggregate = 186lit (for 25-50mm slump range)
Estimate water content for 100 mm slump = 186 + 6/100 * 186
= 197.16 = 198 lit
As a super plasticizer is used the water content can be reduced up to 30%
Based on trial water content reduction of 27% is achieved with plasticizer
Hence arrived content = 198*0.73 = 144.54 = 145 lit
Step 6:- Calculation of cement content
Water-cement ratio = 0.38
Cement content = 145/0.38 = 382= 382 Kg/m^3
From table 5 of IS 456:2000 minimum cement content for severe exposure condition = 320 Kg/m^3
382 Kg/m^3 > 320 Kg/m^3 Hence ok
Take a higher value 382 Kg/m^3
Now to proportion a mix containing fly ash the following steps are suggested
Increase 10% of cementitious material content
Cementitious material content = 382*1.10 = 420 Kg/m^3
Water content = 145 Kg/m^3
so water-cement ratio = 145/420 = 0.345
Fly ash @ 30% total cementitious material = 420*(30/100) = 126 Kg/m^3
Cement (OPC) = 420-126 = 294 Kg/m^3
Saving cement by using fly ash = 382-294 = 88 Kg/m^3
Fly ash being utilized = 126 Kg/m^3
Step 7:- Proportion of volume of coarse aggregate and fine aggregate content
From table 5 of IS 10262:2019 volume of coarse aggregate corresponding to 20mm size aggregate and fine aggregate (zone1) for water-cement ratio of 0.5 = 0.6
In the present case the water-cement ratio is 0.38
The water-cement ratio is reduced to 0.12 therefore the volume of the coarse aggregate needs to be increased to decrease the fine aggregate content
As water-cement ratio is lower by 0.12 the proportion of coarse aggregate is increased by 0.024
Therefore correct volume of coarse aggregate for w/c ratio of 0.29= 0.6+0.024 = 0.624
For pumpable concrete these values are reduced by 10%
therefore volume of coarse aggregate = 0.624*0.9 = 0.56
Volume of fine aggregate = 1-0.56 = 0.44
Step 8:-Mix calculation
The mix calculation per unit volume of concrete shall be as follows
a) Volume of concrete = 1m^3
b) Volume of cement = (Mass of cement /Specific gravity of cement) * (1/1000)
= (294/3.15)*(1/1000) = 0.093m^3
c) Volume of fly ash = (Mass of fly ash /Specific gravity of fly ash) * (1/1000)
= (126/2.2)*(1/1000) = 0.057m^3
d) Volume of water = (Mass of water/Specific gravity of water) * (1/1000)
= (145/1)*(1/1000) = 0.145 m^3
e) Volume of chemical admixture = (Mass of chemical admixture /Specific gravity of chemical admixture) * (1/1000)
Mass of chemical admixture = 2% of cementitious material
= (420*2/100) = 8.4
Volume of chemical admixture = (Mass of chemical admixture /Specific gravity of chemical admixture) * (1/1000)
= (8.4/1.145)*(1/1000) = 0.007m^3
f) Volume of aggregate (fine aggregate and coarse aggregate ) = (a-(b+c+d+e))
= (1-(0.093+0.057+0.145+0.007)
= 0.698 m^3
g) Mass of coarse aggregate = f*volume of coarse aggregate * specific gravity of coarse aggregate * 1000
= 0.698*0.56*2.74*1000 = 1071Kg/m^3
h) Mass of fine aggregate = f*volume of fine aggregate * specific gravity of fine aggregate * 1000
= 0.698*0.44*2.74*1000 = 842Kg/m^3
Step 9:- Mix proportion for trial mix
Trial mix ratio = 1:2:2.55
Result
Concrete mix design for M-50 grade without fly ash
Aim:- To determine the workability of the fresh concrete by using IS 456:2000 and IS 10262:2019 for concrete mix design for M-50 grade without fly ash
Introduction
The process of selecting suitable ingredients for producing concrete of required strength, durability and workability as economical as possible is known as concrete mix design
Code books used are - IS456:2000 and IS 10262:2019
Step 1 :-Stipulation for proportion
Here all the values, types of ingredients, conditions and methods are assumption except grade of designation because the values are not mentioned in questions
Step 2:- Test data for materials
Step 3:- Target strength mix
f'ck= fck+1.65*S
f'ck = target average compressive strength at 28 days
fck = characteristic compressive strength at 28days
S = Standard deviation
From table 2 of IS 10262:2019 standard deviation S = 5 N/mm^2
f'ck = 50+1.65*5
f'ck = 58.25 N/mm^2
Target mean strength = 58.25 N/mm^2
Step 4:- Selection of water-cement ratio
From table 5 of IS 456:2000 for severe exposure maximum water-cement ratio = 0.45
By using a fig 1 of IS 10262:2019 w/c ratio = 0.29
0.29<0.45 ( take lesser value)
Water-cement ratio = 0.29
Hence ok
Step 5:- Selection of water content
From table 4 of IS 10262:2019 maximum water content for 20mm aggregate = 186lit (for 25-50mm slump range)
Estimate water content for 100 mm slump = 186 + 6/100 * 186
= 197.16 = 198 lit
As a super plasticizer is used the water content can be reduced up to 30%
Based on trial water content reduction of 27% is achieved with plasticizer
Hence arrived content = 198*0.73 = 144.54 = 145 lit
Step 6:- Calculation of cement content
Water-cement ratio = 0.29
Cement content = 145/0.29 = 500 = 500 Kg/m^3
From table 5 of IS 456:2000 minimum cement content for severe exposure condition = 320 Kg/m^3
500 Kg/m^3 > 320 Kg/m^3 Hence ok
Take a higher value 500 Kg/m^3
Step 7:- Proportion of volume of coarse aggregate and fine aggregate content
From table 5 of IS 10262:2019 volume of coarse aggregate corresponding to 20mm size aggregate and fine aggregate (zone1) for water-cement ratio of 0.5 = 0.6
In the present case the water-cement ratio is 0.29
The water-cement ratio is reduced to 0.21 therefore the volume of the coarse aggregate needs to be increased to decrease the fine aggregate content
As water-cement ratio is lower by 0.21the proportion of coarse aggregate is increased by 0.042
Therefore correct volume of coarse aggregate for w/c ratio of 0.29= 0.6+0.042 = 0.642
For pumpable concrete these values are reduced by 10%
therefore volume of coarse aggregate = 0.642*0.9 = 0.58
Volume of fine aggregate = 1-0.58 = 0.42
Step 8:-Mix calculation
The mix calculation per unit volume of concrete shall be as follows
a) Volume of concrete = 1m^3
b) Volume of cement = (Mass of cement /Specific gravity of cement) * (1/1000)
= (500/3.15)*(1/1000) = 0.159 m^3
c) Volume of water = (Mass of water/Specific gravity of water) * (1/1000)
= (145/1)*(1/1000) = 0.145 m^3
d) Volume of chemical admixture = (Mass of chemical admixture /Specific gravity of chemical admixture) * (1/1000)
Mass of chemical admixture = 2% of cementitious material
= (500*2/100) = 10
Volume of chemical admixture = (Mass of chemical admixture /Specific gravity of chemical admixture) * (1/1000)
= (10/1.145)*(1/1000) = 0.009 m^3
e) Volume of aggregate (fine aggregate and coarse aggregate ) = (a-(b+c+d))
= (1-(0.159+0.145+0.009)
= 0.687 m^3
f) Mass of coarse aggregate = e*volume of coarse aggregate * specific gravity of coarse aggregate * 1000
= 0.687*0.58*2.74*1000 = 1092Kg/m^3
g) Mass of fine aggregate = e*volume of fine aggregate * specific gravity of fine aggregate * 1000
= 0.687*0.42*2.74*1000 = 791 Kg/m^3
Step 9:- Mix proportion for trial mix
Trial mix ratio = 1:1.582:2.184
Result:-
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