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AIM To Calculate the Concrete Mix Design for M35 grade concrete with fly ash. OBJECTIVES The main objective is to make a concrete most economical with practical combinations of different ingredients. To afflict a balance between the requirements of placement,such as workability,ductility,and strength for M35 grade of concrete.…
Samiksha dhole
updated on 30 May 2022
AIM
To Calculate the Concrete Mix Design for M35 grade concrete with fly ash.
OBJECTIVES
CODES USE FOR MIX DESIGN CONCRETE
PROCEDURE AND CALCULATIONS
1.Target Strength For Mix Proportioning
In order that not more than the specified proportion of test results are likely to fall below the characteristic strength,the concrete mix has to be proportioned for higher target mean compessive strength fck.The margin over characteristic strength is given by the following relation:
f'ck=fck+1.65s
where,
f'ck=Target mean compressive strength at 28days in N/mm^2.
fck=Characteristic compressive strength at 28 days in N/mm^2.
s=Standard deviation N/mm^2.
Thus,For M35,
According to IS code 10262:2009
fck=35N/mm^2,s=5
f'ck=35+(1.65x5)=35+8.25=43.25 N/mm^2.
f'ck=43.25 N/mm^2.
2.Selection of water-cement ratio
From table 5 of IS 456,maximum water-cement ratio for M35 is 0.45.
Assume for Exposure Extreme condition,that is 0.40.
Lower the water-cement ratio better is the workability.
Based on experience,adopt water-cement ratio as 0.40.
Therefore 0.40<0.45,Hence ok.
Water-cement ratio=0.40
Minimum Cement Content=360kg/m^3.
3.Selection of water content
Assume,Nominal Size of aggregate=20mm
From table 2,10262:2009
Maximum water content for 20mm nominal maximum size of aggregate is=186 litre or kg.
Slump ranges from 25 or 50mm,but according to the specification our concrete requires a slump of 100 mm.Clause 4.2 of IS1026 recommends increasing the water content by 3% to obtain an additional 25 mm slump. Therefore, to obtain a slump of 50 mm in addition to our concrete, the water content must be increased by 6%.
-Water content for 100mm slump=186+(0.06x186)=198 litre
As superplasticizers can be reduced to 29%.(based on trial)
=198x0.71=140litre
water content=140 litre
4.Calculation of Cementitious Material Content(cement+fly ash)
Since fly ash is used, the amount of cementitious content (cement + fly ash) should be increased to get good performance and strength. Here we have increased the cementitious content by 10%.
Water-cement ratio=0.40
Total cementitious requirement=Water content/Water cement ratio
=140/0.40=350kg/m^3.
From table 5 of IS 456,minimum cement content for severe exposure conditions=320kg/m^3.
350kg/m^3 >320kg/m^3
Hence ok.
Now,to proportion a mix containing fly ash,
Increase 10% of cementitious material content.
Cementitious Cement Content=350x1.10=385kg/m^3.
water content=140 litre
so,water-cement ratio=140/385=0.364
Fly ash @30% of total cementitious material content =385x30/100=115.5kg/m^3.
Cement (opc)=385-115=270kg/m^3
Saving of cement while using fly ash=350-270=80kg/m^3.
Fly ash being utilized=115kg/m^3.
5.Proportion of volume of coarse aggregate and fine aggregate content
From table 3,Volume of coarse aggregate and fine aggregate (zone 1)water cement ratio for nominal size aggregate of 20mm is 0.60
Volume of aggrregate=0.60,water-cement ratio=0.40
As the water-cement ratio is lower by 0.10 the proportion of volume of coarse aggregate is increased by 0.02(at the rate of ± 0.01 for every ± 0.05 change in water-cement ratio).Therefore,corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.40 is 0.62.
(For pumpable concrete these values should be reduced by 10% but I have not assumed pumpable concrete here in the calculation)
Therefore,Volume of coarse aggregate=0.62
Volume of fine aggregate=1-0.62=0.38
6.Mix Calculation
The mix calculation per unit volume of concrete shall as follows:
RESULT AND CONCLUSION
MIX PROPORTION TRIAL
Cement=270kg/m^3
Fly ash=115kg/m^3
Water=140kg/m^3
Fine aggregate=744.458kg/m^3
Coarse aggregate=1214.642kg/m^3
Chemical admixture=7.6kg/m^3
Water cement ratio=0.40
Trial mix ratio=270: 744.458: 1214.642=1: 2.75: 4.5 (Cement:FA:CA)
AIM
To Calculate the Concrete Mix Design for M50 grade concrete without Fly ash.
OBJECTIVES
CODES USE FOR MIX DESIGN CONCRETE
PROCEDURE AND CALCULATIONS
1.Target Strength For Mix Proportioning
In order that not more than the specified proportion of test results are likely to fall below the characteristic strength,the concrete mix has to be proportioned for higher target mean compessive strength fck.The margin over characteristic strength is given by the following relation:
f'ck=fck+1.65s
where,
f'ck=Target mean compressive strength at 28days in N/mm^2.
fck=Characteristic compressive strength at 28 days in N/mm^2.
s=Standard deviation N/mm^2.
Thus,For M50,
According to IS code 10262:2009
fck=50N/mm^2,s=5
f'ck=50+(1.65x5)=50+8.25=58.25 N/mm^2.
f'ck=58.25 N/mm^2.
2.Selection of water-cement ratio
From table 5 of IS 456,maximum water-cement ratio for M50 is 0.40.
Assume for Exposure Extreme condition,that is 0.40.
Based on experience,adopt water-cement ratio as 0.40.
Water-cement ratio=0.40
Minimum Cement Content=360kg/m^3.
3.Selection of water content
Assume,Nominal Size of aggregate=20mm
From table 2,10262:2009
Maximum water content for 20mm nominal maximum size of aggregate is=186 litre or kg.
Slump ranges from 25 or 50mm,but according to the specification our concrete requires a slump of 100 mm.Clause 4.2 of IS1026 recommends increasing the water content by 3% to obtain an additional 25 mm slump. Therefore, to obtain a slump of 50 mm in addition to our concrete, the water content must be increased by 6%.
-Water content for 100mm slump=186+(0.06x186)=198 litre
As superplasticizers can be reduced to 29%.(based on trial)
=198x0.71=140litre
water content=140 litre
4.Calculation of Cement Content
Water-cement ratio=0.40
Total cement requirement=Water content/Water cement ratio
=140/0.40=350kg/m^3.
From table 5 of IS 456,minimum cement content for severe exposure conditions=320kg/m^3.
350kg/m^3 >320kg/m^3
Hence ok.
5.Proportion of volume of coarse aggregate and fine aggregate content
From table 3,Volume of coarse aggregate and fine aggregate (zone 1)water cement ratio for nominal size aggregate of 20mm is 0.60.
Volume of aggrregate=0.60,water-cement ratio=0.40
As the water-cement ratio is lower by 0.10 the proportion of volume of coarse aggregate is increased by 0.02(at the rate of ± 0.01 for every ± 0.05 change in water-cement ratio).Therefore,corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.40 is 0.62.
(For pumpable concrete these values should be reduced by 10% but I have not assumed pumpable concrete here in the calculation)
Therefore,Volume of coarse aggregate=0.62
Volume of fine aggregate=1-0.62=0.38
6.Mix Calculation
The mix calculation per unit volume of concrete shall as follows:
RESULT AND CONCLUSION
MIX PROPORTION TRIAL
Cement=350kg/m^3
Water=140kg/m^3
Fine aggregate=772.57kg/m^3
Coarse aggregate=1260.50kg/m^3
Chemical admixture=7.6kg/m^3
Water cement ratio=0.40
Trial mix ratio=350: 772.57: 1260.50=1: 2.20: 3.60 (Cement:FA:CA)
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